Base | Representation |
---|---|
bin | 100000000111111100111… |
… | …1101101111010010010011 |
3 | 120122002012122211222210202 |
4 | 1000033321331233102103 |
5 | 1034314134012433433 |
6 | 13220140330045415 |
7 | 633660626226221 |
oct | 100177175572223 |
9 | 16562178758722 |
10 | 4415125124243 |
11 | 1452498037749 |
12 | 5b382057986b |
13 | 260462b82222 |
14 | 11399c1b7b11 |
15 | 79caa681ee8 |
hex | 403f9f6f493 |
4415125124243 has 2 divisors, whose sum is σ = 4415125124244. Its totient is φ = 4415125124242.
The previous prime is 4415125124239. The next prime is 4415125124357. The reversal of 4415125124243 is 3424215215144.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4415125124243 - 22 = 4415125124239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4415125124197 and 4415125124206.
It is not a weakly prime, because it can be changed into another prime (4415125124233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2207562562121 + 2207562562122.
It is an arithmetic number, because the mean of its divisors is an integer number (2207562562122).
Almost surely, 24415125124243 is an apocalyptic number.
4415125124243 is a deficient number, since it is larger than the sum of its proper divisors (1).
4415125124243 is an equidigital number, since it uses as much as digits as its factorization.
4415125124243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 153600, while the sum is 38.
Subtracting from 4415125124243 its reverse (3424215215144), we obtain a palindrome (990909909099).
The spelling of 4415125124243 in words is "four trillion, four hundred fifteen billion, one hundred twenty-five million, one hundred twenty-four thousand, two hundred forty-three".
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