Base | Representation |
---|---|
bin | 10100000110101110000010… |
… | …10011010100000010000001 |
3 | 12210112120012101211101222221 |
4 | 22003113001103110002001 |
5 | 21243324311402140301 |
6 | 234010224310531041 |
7 | 12212110153505002 |
oct | 1203270123240201 |
9 | 183476171741887 |
10 | 44211341443201 |
11 | 130a5a19725a99 |
12 | 4b60554966a81 |
13 | 1b8915b2881aa |
14 | acbba9c8b1a9 |
15 | 51a089b83da1 |
hex | 2835c14d4081 |
44211341443201 has 2 divisors, whose sum is σ = 44211341443202. Its totient is φ = 44211341443200.
The previous prime is 44211341443187. The next prime is 44211341443229. The reversal of 44211341443201 is 10234414311244.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31241403538801 + 12969937904400 = 5589401^2 + 3601380^2 .
It is a cyclic number.
It is not a de Polignac number, because 44211341443201 - 215 = 44211341410433 is a prime.
It is not a weakly prime, because it can be changed into another prime (44211341443231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22105670721600 + 22105670721601.
It is an arithmetic number, because the mean of its divisors is an integer number (22105670721601).
Almost surely, 244211341443201 is an apocalyptic number.
It is an amenable number.
44211341443201 is a deficient number, since it is larger than the sum of its proper divisors (1).
44211341443201 is an equidigital number, since it uses as much as digits as its factorization.
44211341443201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 44211341443201 its reverse (10234414311244), we get a palindrome (54445755754445).
The spelling of 44211341443201 in words is "forty-four trillion, two hundred eleven billion, three hundred forty-one million, four hundred forty-three thousand, two hundred one".
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