Base | Representation |
---|---|
bin | 100000001011101011100… |
… | …1110010101000000111001 |
3 | 120122211212200120211211111 |
4 | 1000113113032111000321 |
5 | 1034432033321030423 |
6 | 13223543041400321 |
7 | 634363224260266 |
oct | 100272716250071 |
9 | 16584780524744 |
10 | 4423132205113 |
11 | 1455926901056 |
12 | 5b52960390a1 |
13 | 26113aa042bb |
14 | 11411b7a626d |
15 | 7a0c85ca60d |
hex | 405d7395039 |
4423132205113 has 2 divisors, whose sum is σ = 4423132205114. Its totient is φ = 4423132205112.
The previous prime is 4423132205099. The next prime is 4423132205183. The reversal of 4423132205113 is 3115022313244.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3932499200809 + 490633004304 = 1983053^2 + 700452^2 .
It is a cyclic number.
It is not a de Polignac number, because 4423132205113 - 233 = 4414542270521 is a prime.
It is not a weakly prime, because it can be changed into another prime (4423132205183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2211566102556 + 2211566102557.
It is an arithmetic number, because the mean of its divisors is an integer number (2211566102557).
Almost surely, 24423132205113 is an apocalyptic number.
It is an amenable number.
4423132205113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4423132205113 is an equidigital number, since it uses as much as digits as its factorization.
4423132205113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 4423132205113 its reverse (3115022313244), we get a palindrome (7538154518357).
The spelling of 4423132205113 in words is "four trillion, four hundred twenty-three billion, one hundred thirty-two million, two hundred five thousand, one hundred thirteen".
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