Base | Representation |
---|---|
bin | 110010010011001011010101… |
… | …1010111000011101000111011 |
3 | 2011000112212212002100001001211 |
4 | 1210212112223113003220323 |
5 | 430442420304244323003 |
6 | 4204554141532223551 |
7 | 162123155050234216 |
oct | 14446265327035073 |
9 | 2130485762301054 |
10 | 442440341011003 |
11 | 118a7a993117565 |
12 | 41757a9b00abb7 |
13 | 15cb4c395c700a |
14 | 7b3832635077d |
15 | 3623d4e11896d |
hex | 19265ab5c3a3b |
442440341011003 has 2 divisors, whose sum is σ = 442440341011004. Its totient is φ = 442440341011002.
The previous prime is 442440341010979. The next prime is 442440341011033. The reversal of 442440341011003 is 300110143044244.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 442440341011003 - 213 = 442440341002811 is a prime.
It is not a weakly prime, because it can be changed into another prime (442440341011033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221220170505501 + 221220170505502.
It is an arithmetic number, because the mean of its divisors is an integer number (221220170505502).
Almost surely, 2442440341011003 is an apocalyptic number.
442440341011003 is a deficient number, since it is larger than the sum of its proper divisors (1).
442440341011003 is an equidigital number, since it uses as much as digits as its factorization.
442440341011003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 442440341011003 its reverse (300110143044244), we get a palindrome (742550484055247).
The spelling of 442440341011003 in words is "four hundred forty-two trillion, four hundred forty billion, three hundred forty-one million, eleven thousand, three".
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