Base | Representation |
---|---|
bin | 110010010011001011101101… |
… | …0011000111110010000101011 |
3 | 2011000112221220002000222200022 |
4 | 1210212113122120332100223 |
5 | 430442423413242324121 |
6 | 4204554352120031055 |
7 | 162123213441005303 |
oct | 14446273230762053 |
9 | 2130487802028608 |
10 | 442441130042411 |
11 | 118a80258546535 |
12 | 4175807b30248b |
13 | 15cb5033c094c6 |
14 | 7b3839d062603 |
15 | 3623d98525aab |
hex | 19265da63e42b |
442441130042411 has 4 divisors (see below), whose sum is σ = 444885556175424. Its totient is φ = 439996703909400.
The previous prime is 442441130042383. The next prime is 442441130042501. The reversal of 442441130042411 is 114240031144244.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-442441130042411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (442441130042111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1222213066235 + ... + 1222213066596.
It is an arithmetic number, because the mean of its divisors is an integer number (111221389043856).
Almost surely, 2442441130042411 is an apocalyptic number.
442441130042411 is a deficient number, since it is larger than the sum of its proper divisors (2444426133013).
442441130042411 is a wasteful number, since it uses less digits than its factorization.
442441130042411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2444426133012.
The product of its (nonzero) digits is 49152, while the sum is 35.
Adding to 442441130042411 its reverse (114240031144244), we get a palindrome (556681161186655).
The spelling of 442441130042411 in words is "four hundred forty-two trillion, four hundred forty-one billion, one hundred thirty million, forty-two thousand, four hundred eleven".
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