Base | Representation |
---|---|
bin | 100000001111010111011… |
… | …0011110100010011010011 |
3 | 120200121022002012211001202 |
4 | 1000132232303310103103 |
5 | 1040044234242220311 |
6 | 13231332113021415 |
7 | 635063255263151 |
oct | 100365663642323 |
9 | 16617262184052 |
10 | 4431044101331 |
11 | 1459216972861 |
12 | 5b692385486b |
13 | 261acbc0a5b3 |
14 | 11466c4983d1 |
15 | 7a3dcec0e3b |
hex | 407aecf44d3 |
4431044101331 has 2 divisors, whose sum is σ = 4431044101332. Its totient is φ = 4431044101330.
The previous prime is 4431044101291. The next prime is 4431044101339. The reversal of 4431044101331 is 1331014401344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4431044101331 - 214 = 4431044084947 is a prime.
It is a super-2 number, since 2×44310441013312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4431044101294 and 4431044101303.
It is not a weakly prime, because it can be changed into another prime (4431044101339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215522050665 + 2215522050666.
It is an arithmetic number, because the mean of its divisors is an integer number (2215522050666).
Almost surely, 24431044101331 is an apocalyptic number.
4431044101331 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431044101331 is an equidigital number, since it uses as much as digits as its factorization.
4431044101331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 4431044101331 its reverse (1331014401344), we get a palindrome (5762058502675).
The spelling of 4431044101331 in words is "four trillion, four hundred thirty-one billion, forty-four million, one hundred one thousand, three hundred thirty-one".
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