Base | Representation |
---|---|
bin | 100000001111011001110… |
… | …1010000110100000001011 |
3 | 120200121111202021021110102 |
4 | 1000132303222012200023 |
5 | 1040044421103044043 |
6 | 13231344140240015 |
7 | 635065263534515 |
oct | 100366352064013 |
9 | 16617452237412 |
10 | 4431125440523 |
11 | 1459258879131 |
12 | 5b6946b4000b |
13 | 261b12a193b2 |
14 | 1146791ccbb5 |
15 | 7a3e51db6b8 |
hex | 407b3a8680b |
4431125440523 has 2 divisors, whose sum is σ = 4431125440524. Its totient is φ = 4431125440522.
The previous prime is 4431125440501. The next prime is 4431125440631. The reversal of 4431125440523 is 3250445211344.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4431125440523 - 216 = 4431125374987 is a prime.
It is not a weakly prime, because it can be changed into another prime (4431125440823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215562720261 + 2215562720262.
It is an arithmetic number, because the mean of its divisors is an integer number (2215562720262).
Almost surely, 24431125440523 is an apocalyptic number.
4431125440523 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431125440523 is an equidigital number, since it uses as much as digits as its factorization.
4431125440523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 38.
The spelling of 4431125440523 in words is "four trillion, four hundred thirty-one billion, one hundred twenty-five million, four hundred forty thousand, five hundred twenty-three".
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