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4431234304113 = 31477078101371
BaseRepresentation
bin100000001111011101000…
…1001011000100001110001
3120200121210100010010020020
41000132322021120201301
51040100131440212423
613231403025434053
7635101055054211
oct100367211304161
916617710103206
104431234304113
111459304273a41
125b697749b929
13261b2c444416
1411468984a241
157a3eea424e3
hex407ba258871

4431234304113 has 4 divisors (see below), whose sum is σ = 5908312405488. Its totient is φ = 2954156202740.

The previous prime is 4431234304087. The next prime is 4431234304121. The reversal of 4431234304113 is 3114034321344.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4431234304113 - 28 = 4431234303857 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4431234304153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 738539050683 + ... + 738539050688.

It is an arithmetic number, because the mean of its divisors is an integer number (1477078101372).

Almost surely, 24431234304113 is an apocalyptic number.

It is an amenable number.

4431234304113 is a deficient number, since it is larger than the sum of its proper divisors (1477078101375).

4431234304113 is a wasteful number, since it uses less digits than its factorization.

4431234304113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1477078101374.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 4431234304113 its reverse (3114034321344), we get a palindrome (7545268625457).

The spelling of 4431234304113 in words is "four trillion, four hundred thirty-one billion, two hundred thirty-four million, three hundred four thousand, one hundred thirteen".

Divisors: 1 3 1477078101371 4431234304113