Base | Representation |
---|---|
bin | 100000001111011111011… |
… | …0101101000010101010011 |
3 | 120200121222211012220020001 |
4 | 1000132332311220111103 |
5 | 1040100312112341201 |
6 | 13231414520430431 |
7 | 635103032056342 |
oct | 100367665502523 |
9 | 16617884186201 |
10 | 4431313012051 |
11 | 1459344742422 |
12 | 5b6999918417 |
13 | 261b42841673 |
14 | 114696097b59 |
15 | 7a4068dd301 |
hex | 407bed68553 |
4431313012051 has 2 divisors, whose sum is σ = 4431313012052. Its totient is φ = 4431313012050.
The previous prime is 4431313012033. The next prime is 4431313012057. The reversal of 4431313012051 is 1502103131344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4431313012051 - 227 = 4431178794323 is a prime.
It is not a weakly prime, because it can be changed into another prime (4431313012057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215656506025 + 2215656506026.
It is an arithmetic number, because the mean of its divisors is an integer number (2215656506026).
Almost surely, 24431313012051 is an apocalyptic number.
4431313012051 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431313012051 is an equidigital number, since it uses as much as digits as its factorization.
4431313012051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 4431313012051 its reverse (1502103131344), we get a palindrome (5933416143395).
The spelling of 4431313012051 in words is "four trillion, four hundred thirty-one billion, three hundred thirteen million, twelve thousand, fifty-one".
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