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44313130131 = 314771043377
BaseRepresentation
bin101001010001010001…
…001011010010010011
311020101020222020201220
4221101101023102103
51211223130131011
632205052100123
73126056251134
oct512121132223
9136336866656
1044313130131
111787a6745a6
128708464643
13424281b27a
142205351c8b
1512454b1506
hexa5144b493

44313130131 has 4 divisors (see below), whose sum is σ = 59084173512. Its totient is φ = 29542086752.

The previous prime is 44313130109. The next prime is 44313130193. The reversal of 44313130131 is 13103131344.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 44313130131 - 221 = 44311032979 is a prime.

It is a super-2 number, since 2×443131301312 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (44313130831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7385521686 + ... + 7385521691.

It is an arithmetic number, because the mean of its divisors is an integer number (14771043378).

Almost surely, 244313130131 is an apocalyptic number.

44313130131 is a deficient number, since it is larger than the sum of its proper divisors (14771043381).

44313130131 is a wasteful number, since it uses less digits than its factorization.

44313130131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14771043380.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 44313130131 its reverse (13103131344), we get a palindrome (57416261475).

The spelling of 44313130131 in words is "forty-four billion, three hundred thirteen million, one hundred thirty thousand, one hundred thirty-one".

Divisors: 1 3 14771043377 44313130131