Base | Representation |
---|---|
bin | 1100111001100001100… |
… | …10101110001010010001 |
3 | 1120100222101102122102021 |
4 | 12130300302232022101 |
5 | 24230133224443004 |
6 | 535334155051441 |
7 | 44006625555322 |
oct | 6346062561221 |
9 | 1510871378367 |
10 | 443200234129 |
11 | 160a61a83734 |
12 | 71a8aa40b81 |
13 | 32a41711b63 |
14 | 176457ba449 |
15 | b7de327d54 |
hex | 6730cae291 |
443200234129 has 2 divisors, whose sum is σ = 443200234130. Its totient is φ = 443200234128.
The previous prime is 443200234123. The next prime is 443200234193. The reversal of 443200234129 is 921432002344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 442457780625 + 742453504 = 665175^2 + 27248^2 .
It is a cyclic number.
It is not a de Polignac number, because 443200234129 - 223 = 443191845521 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 443200234094 and 443200234103.
It is not a weakly prime, because it can be changed into another prime (443200234123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221600117064 + 221600117065.
It is an arithmetic number, because the mean of its divisors is an integer number (221600117065).
Almost surely, 2443200234129 is an apocalyptic number.
It is an amenable number.
443200234129 is a deficient number, since it is larger than the sum of its proper divisors (1).
443200234129 is an equidigital number, since it uses as much as digits as its factorization.
443200234129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
It can be divided in two parts, 443200 and 234129, that added together give a square (677329 = 8232).
The spelling of 443200234129 in words is "four hundred forty-three billion, two hundred million, two hundred thirty-four thousand, one hundred twenty-nine".
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