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44320140042011 = 191232042618021
BaseRepresentation
bin10100001001111000101100…
…01101000001111100011011
312210220222000202120212202122
422010330112031001330123
521302120121322321021
6234132220302251455
712223011246363041
oct1204742615017433
9183828022525678
1044320140042011
111313807a6a2659
124b79659286b8b
131b964a98bcc02
14ad316b698391
1551cd06565bab
hex284f16341f1b

44320140042011 has 4 divisors (see below), whose sum is σ = 44552182660224. Its totient is φ = 44088097423800.

The previous prime is 44320140041999. The next prime is 44320140042053. The reversal of 44320140042011 is 11024004102344.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44320140042011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44320140042911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116021308820 + ... + 116021309201.

It is an arithmetic number, because the mean of its divisors is an integer number (11138045665056).

Almost surely, 244320140042011 is an apocalyptic number.

44320140042011 is a deficient number, since it is larger than the sum of its proper divisors (232042618213).

44320140042011 is a wasteful number, since it uses less digits than its factorization.

44320140042011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 232042618212.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 44320140042011 its reverse (11024004102344), we get a palindrome (55344144144355).

The spelling of 44320140042011 in words is "forty-four trillion, three hundred twenty billion, one hundred forty million, forty-two thousand, eleven".

Divisors: 1 191 232042618021 44320140042011