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4432032011141 = 74332939447019
BaseRepresentation
bin100000001111110100110…
…1100011001001110000101
3120200200211221010211112222
41000133221230121032011
51040103300143324031
613232014123222125
7635126612340530
oct100375154311605
916620757124488
104432032011141
111459683589049
125b6b5a677945
13261c287a3707
14114723779a17
157a449ab4e7b
hex407e9b19385

4432032011141 has 16 divisors (see below), whose sum is σ = 5183143257600. Its totient is φ = 3710417478768.

The previous prime is 4432032011101. The next prime is 4432032011233. The reversal of 4432032011141 is 1411102302344.

It is not a de Polignac number, because 4432032011141 - 230 = 4430958269317 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4432032011141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4432032011101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9691130 + ... + 10138148.

It is an arithmetic number, because the mean of its divisors is an integer number (323946453600).

Almost surely, 24432032011141 is an apocalyptic number.

It is an amenable number.

4432032011141 is a deficient number, since it is larger than the sum of its proper divisors (751111246459).

4432032011141 is a wasteful number, since it uses less digits than its factorization.

4432032011141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 480008.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 4432032011141 its reverse (1411102302344), we get a palindrome (5843134313485).

The spelling of 4432032011141 in words is "four trillion, four hundred thirty-two billion, thirty-two million, eleven thousand, one hundred forty-one".

Divisors: 1 7 43 301 32939 230573 447019 1416377 3129133 9914639 19221817 134552719 14724358841 103070511887 633147430163 4432032011141