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4432214113 = 19972404891
BaseRepresentation
bin1000010000010111…
…00011100001100001
3102102212222210202021
410020023203201201
533034121322423
62011445421441
7214556125015
oct41013434141
912385883667
104432214113
111974962078
12a3840a881
13558331a02
14300902545
151ae19d95d
hex1082e3861

4432214113 has 8 divisors (see below), whose sum is σ = 4713588320. Its totient is φ = 4155649920.

The previous prime is 4432214099. The next prime is 4432214117. The reversal of 4432214113 is 3114122344.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4432214113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4432214117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1200603 + ... + 1204288.

It is an arithmetic number, because the mean of its divisors is an integer number (589198540).

Almost surely, 24432214113 is an apocalyptic number.

It is an amenable number.

4432214113 is a deficient number, since it is larger than the sum of its proper divisors (281374207).

4432214113 is a wasteful number, since it uses less digits than its factorization.

4432214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2405007.

The product of its digits is 2304, while the sum is 25.

The square root of 4432214113 is about 66574.8759893700. The cubic root of 4432214113 is about 1642.6318678448.

Adding to 4432214113 its reverse (3114122344), we get a palindrome (7546336457).

The spelling of 4432214113 in words is "four billion, four hundred thirty-two million, two hundred fourteen thousand, one hundred thirteen".

Divisors: 1 19 97 1843 2404891 45692929 233274427 4432214113