Base | Representation |
---|---|
bin | 101001010001110111… |
… | …001100000000100001 |
3 | 11020101221201111100212 |
4 | 221101313030000201 |
5 | 1211233203011221 |
6 | 32210045423505 |
7 | 3126240042014 |
oct | 512167140041 |
9 | 136357644325 |
10 | 44323094561 |
11 | 1788525aa69 |
12 | 870b86ab95 |
13 | 42448c9895 |
14 | 22067c737b |
15 | 12462cdb5b |
hex | a51dcc021 |
44323094561 has 2 divisors, whose sum is σ = 44323094562. Its totient is φ = 44323094560.
The previous prime is 44323094539. The next prime is 44323094573. The reversal of 44323094561 is 16549032344.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39648774400 + 4674320161 = 199120^2 + 68369^2 .
It is a cyclic number.
It is not a de Polignac number, because 44323094561 - 234 = 27143225377 is a prime.
It is a super-2 number, since 2×443230945612 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (44323096561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22161547280 + 22161547281.
It is an arithmetic number, because the mean of its divisors is an integer number (22161547281).
Almost surely, 244323094561 is an apocalyptic number.
It is an amenable number.
44323094561 is a deficient number, since it is larger than the sum of its proper divisors (1).
44323094561 is an equidigital number, since it uses as much as digits as its factorization.
44323094561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 44323094561 in words is "forty-four billion, three hundred twenty-three million, ninety-four thousand, five hundred sixty-one".
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