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4432323412441 is a prime number
BaseRepresentation
bin100000001111111101100…
…0100000000000111011001
3120200201121020110112222201
41000133323010000013121
51040104344243144231
613232103053050201
7635140051245151
oct100377304000731
916621536415881
104432323412441
11145981301a171
125b7020186961
13261c73c80712
14114750351761
157a465476161
hex407fb1001d9

4432323412441 has 2 divisors, whose sum is σ = 4432323412442. Its totient is φ = 4432323412440.

The previous prime is 4432323412417. The next prime is 4432323412459. The reversal of 4432323412441 is 1442143232344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3638613475225 + 793709937216 = 1907515^2 + 890904^2 .

It is a cyclic number.

It is not a de Polignac number, because 4432323412441 - 219 = 4432322888153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4432323412441.

It is not a weakly prime, because it can be changed into another prime (4432323412241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2216161706220 + 2216161706221.

It is an arithmetic number, because the mean of its divisors is an integer number (2216161706221).

Almost surely, 24432323412441 is an apocalyptic number.

It is an amenable number.

4432323412441 is a deficient number, since it is larger than the sum of its proper divisors (1).

4432323412441 is an equidigital number, since it uses as much as digits as its factorization.

4432323412441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 221184, while the sum is 37.

Adding to 4432323412441 its reverse (1442143232344), we get a palindrome (5874466644785).

The spelling of 4432323412441 in words is "four trillion, four hundred thirty-two billion, three hundred twenty-three million, four hundred twelve thousand, four hundred forty-one".