Base | Representation |
---|---|
bin | 101001010001111011… |
… | …011100010111000001 |
3 | 11020102000211011121121 |
4 | 221101323130113001 |
5 | 1211233444210423 |
6 | 32210125352241 |
7 | 3126252366241 |
oct | 512173342701 |
9 | 136360734547 |
10 | 44324210113 |
11 | 17885952107 |
12 | 8710108681 |
13 | 4244bca581 |
14 | 22069d7b21 |
15 | 124644e45d |
hex | a51edc5c1 |
44324210113 has 4 divisors (see below), whose sum is σ = 44349015600. Its totient is φ = 44299404628.
The previous prime is 44324210107. The next prime is 44324210171. The reversal of 44324210113 is 31101242344.
44324210113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-44324210113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (44324210213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12400063 + ... + 12403636.
It is an arithmetic number, because the mean of its divisors is an integer number (11087253900).
Almost surely, 244324210113 is an apocalyptic number.
It is an amenable number.
44324210113 is a deficient number, since it is larger than the sum of its proper divisors (24805487).
44324210113 is a wasteful number, since it uses less digits than its factorization.
44324210113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24805486.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 44324210113 its reverse (31101242344), we get a palindrome (75425452457).
The spelling of 44324210113 in words is "forty-four billion, three hundred twenty-four million, two hundred ten thousand, one hundred thirteen".
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