Base | Representation |
---|---|
bin | 100000010000010101000… |
… | …0101011000011010001001 |
3 | 120200210122012220100201111 |
4 | 1000200222011120122021 |
5 | 1040113003222200431 |
6 | 13232313233450321 |
7 | 635165440562266 |
oct | 100405205303211 |
9 | 16623565810644 |
10 | 4433112303241 |
11 | 145a088362536 |
12 | 5b72004109a1 |
13 | 26206b543bcb |
14 | 1147c702826d |
15 | 7a4ae8567b1 |
hex | 4082a158689 |
4433112303241 has 2 divisors, whose sum is σ = 4433112303242. Its totient is φ = 4433112303240.
The previous prime is 4433112303233. The next prime is 4433112303247. The reversal of 4433112303241 is 1423032113344.
4433112303241 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3608875287616 + 824237015625 = 1899704^2 + 907875^2 .
It is a cyclic number.
It is not a de Polignac number, because 4433112303241 - 23 = 4433112303233 is a prime.
It is not a weakly prime, because it can be changed into another prime (4433112303247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2216556151620 + 2216556151621.
It is an arithmetic number, because the mean of its divisors is an integer number (2216556151621).
Almost surely, 24433112303241 is an apocalyptic number.
It is an amenable number.
4433112303241 is a deficient number, since it is larger than the sum of its proper divisors (1).
4433112303241 is an equidigital number, since it uses as much as digits as its factorization.
4433112303241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 4433112303241 its reverse (1423032113344), we get a palindrome (5856144416585).
The spelling of 4433112303241 in words is "four trillion, four hundred thirty-three billion, one hundred twelve million, three hundred three thousand, two hundred forty-one".
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