Base | Representation |
---|---|
bin | 100000010000110010110… |
… | …0100100110000100011011 |
3 | 120200220012202212221200212 |
4 | 1000201211210212010123 |
5 | 1040122024221411103 |
6 | 13233000245121335 |
7 | 635232250012451 |
oct | 100414544460433 |
9 | 16626182787625 |
10 | 4434110341403 |
11 | 145a54a766366 |
12 | 5b743a6b924b |
13 | 26219a245132 |
14 | 11487d7c49d1 |
15 | 7a51c29b7d8 |
hex | 4086592611b |
4434110341403 has 2 divisors, whose sum is σ = 4434110341404. Its totient is φ = 4434110341402.
The previous prime is 4434110341399. The next prime is 4434110341421. The reversal of 4434110341403 is 3041430114344.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4434110341403 - 22 = 4434110341399 is a prime.
It is a super-2 number, since 2×44341103414032 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4434110341403.
It is not a weakly prime, because it can be changed into another prime (4434110341303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2217055170701 + 2217055170702.
It is an arithmetic number, because the mean of its divisors is an integer number (2217055170702).
Almost surely, 24434110341403 is an apocalyptic number.
4434110341403 is a deficient number, since it is larger than the sum of its proper divisors (1).
4434110341403 is an equidigital number, since it uses as much as digits as its factorization.
4434110341403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 4434110341403 its reverse (3041430114344), we get a palindrome (7475540455747).
The spelling of 4434110341403 in words is "four trillion, four hundred thirty-four billion, one hundred ten million, three hundred forty-one thousand, four hundred three".
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