Base | Representation |
---|---|
bin | 100000010000111000110… |
… | …1110010011010000111001 |
3 | 120200220201222111200010212 |
4 | 1000201301232103100321 |
5 | 1040122433414244114 |
6 | 13233032410520505 |
7 | 635240303621534 |
oct | 100416156232071 |
9 | 16626658450125 |
10 | 4434314212409 |
11 | 145a6448526a4 |
12 | 5b7496a36135 |
13 | 262200556373 |
14 | 11489c8d3a1b |
15 | 7a53011cb3e |
hex | 40871b93439 |
4434314212409 has 2 divisors, whose sum is σ = 4434314212410. Its totient is φ = 4434314212408.
The previous prime is 4434314212397. The next prime is 4434314212453. The reversal of 4434314212409 is 9042124134344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3008073984400 + 1426240228009 = 1734380^2 + 1194253^2 .
It is a cyclic number.
It is not a de Polignac number, because 4434314212409 - 236 = 4365594735673 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (4434314212709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2217157106204 + 2217157106205.
It is an arithmetic number, because the mean of its divisors is an integer number (2217157106205).
Almost surely, 24434314212409 is an apocalyptic number.
It is an amenable number.
4434314212409 is a deficient number, since it is larger than the sum of its proper divisors (1).
4434314212409 is an equidigital number, since it uses as much as digits as its factorization.
4434314212409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 331776, while the sum is 41.
The spelling of 4434314212409 in words is "four trillion, four hundred thirty-four billion, three hundred fourteen million, two hundred twelve thousand, four hundred nine".
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