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4434404424403 = 31143045304013
BaseRepresentation
bin100000010000111011100…
…0110011011101011010011
3120200220222021020220201211
41000201313012123223103
51040123130013040103
613233045352240551
7635242450456342
oct100416706335323
916626867226654
104434404424403
11145a690769268
125b75010a0157
13262216150945
141148aa897b59
157a537edc36d
hex4087719bad3

4434404424403 has 4 divisors (see below), whose sum is σ = 4577449728448. Its totient is φ = 4291359120360.

The previous prime is 4434404424367. The next prime is 4434404424407. The reversal of 4434404424403 is 3044244044344.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4434404424403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4434404424407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71522651976 + ... + 71522652037.

It is an arithmetic number, because the mean of its divisors is an integer number (1144362432112).

Almost surely, 24434404424403 is an apocalyptic number.

4434404424403 is a deficient number, since it is larger than the sum of its proper divisors (143045304045).

4434404424403 is a wasteful number, since it uses less digits than its factorization.

4434404424403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 143045304044.

The product of its (nonzero) digits is 1179648, while the sum is 40.

Adding to 4434404424403 its reverse (3044244044344), we get a palindrome (7478648468747).

The spelling of 4434404424403 in words is "four trillion, four hundred thirty-four billion, four hundred four million, four hundred twenty-four thousand, four hundred three".

Divisors: 1 31 143045304013 4434404424403