Base | Representation |
---|---|
bin | 100000010011100011001… |
… | …1111110000101010001011 |
3 | 120201110111102110111001221 |
4 | 1000213012133300222023 |
5 | 1040221141021300212 |
6 | 13235420002422511 |
7 | 635532055314313 |
oct | 100470637605213 |
9 | 16643442414057 |
10 | 4440031431307 |
11 | 1462008a9a89a |
12 | 5b8611661a37 |
13 | 262901b72924 |
14 | 114c81d32443 |
15 | 7a766ee8807 |
hex | 409c67f0a8b |
4440031431307 has 2 divisors, whose sum is σ = 4440031431308. Its totient is φ = 4440031431306.
The previous prime is 4440031431301. The next prime is 4440031431317. The reversal of 4440031431307 is 7031341300444.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4440031431307 is a prime.
It is a super-2 number, since 2×44400314313072 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4440031431301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220015715653 + 2220015715654.
It is an arithmetic number, because the mean of its divisors is an integer number (2220015715654).
Almost surely, 24440031431307 is an apocalyptic number.
4440031431307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4440031431307 is an equidigital number, since it uses as much as digits as its factorization.
4440031431307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 34.
The spelling of 4440031431307 in words is "four trillion, four hundred forty billion, thirty-one million, four hundred thirty-one thousand, three hundred seven".
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