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444020333131 is a prime number
BaseRepresentation
bin1100111011000011010…
…11001001101001001011
31120110002112120222202101
412131201223021221023
524233323201130011
6535551412414231
744036144362444
oct6354153115113
91513075528671
10444020333131
111613429a2201
1272079617377
1332b425b123b
14176c26982cb
15b83b3202c1
hex6761ac9a4b

444020333131 has 2 divisors, whose sum is σ = 444020333132. Its totient is φ = 444020333130.

The previous prime is 444020333111. The next prime is 444020333153. The reversal of 444020333131 is 131333020444.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 444020333131 - 215 = 444020300363 is a prime.

It is a super-2 number, since 2×4440203331312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 444020333131.

It is not a weakly prime, because it can be changed into another prime (444020333111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222010166565 + 222010166566.

It is an arithmetic number, because the mean of its divisors is an integer number (222010166566).

Almost surely, 2444020333131 is an apocalyptic number.

444020333131 is a deficient number, since it is larger than the sum of its proper divisors (1).

444020333131 is an equidigital number, since it uses as much as digits as its factorization.

444020333131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 444020333131 its reverse (131333020444), we get a palindrome (575353353575).

The spelling of 444020333131 in words is "four hundred forty-four billion, twenty million, three hundred thirty-three thousand, one hundred thirty-one".