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444110222114953 is a prime number
BaseRepresentation
bin110010011111010100111100…
…0000001111100000010001001
32011020110112002222020102012021
41210332221320001330002021
5431202300213330134303
64212313230335444441
7162354622212355222
oct14476517001740211
92136415088212167
10444110222114953
111195640a64aa719
1241987652986721
13160a65501390b4
147b95099944249
1536524d5674ebd
hex193ea7807c089

444110222114953 has 2 divisors, whose sum is σ = 444110222114954. Its totient is φ = 444110222114952.

The previous prime is 444110222114731. The next prime is 444110222115041. The reversal of 444110222114953 is 359411222011444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 348259308153849 + 95850913961104 = 18661707^2 + 9790348^2 .

It is a cyclic number.

It is not a de Polignac number, because 444110222114953 - 229 = 444109685244041 is a prime.

It is not a weakly prime, because it can be changed into another prime (444110222114653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222055111057476 + 222055111057477.

It is an arithmetic number, because the mean of its divisors is an integer number (222055111057477).

Almost surely, 2444110222114953 is an apocalyptic number.

It is an amenable number.

444110222114953 is a deficient number, since it is larger than the sum of its proper divisors (1).

444110222114953 is an equidigital number, since it uses as much as digits as its factorization.

444110222114953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 276480, while the sum is 43.

The spelling of 444110222114953 in words is "four hundred forty-four trillion, one hundred ten billion, two hundred twenty-two million, one hundred fourteen thousand, nine hundred fifty-three".