Base | Representation |
---|---|
bin | 1100111011001110011… |
… | …00101001111000100011 |
3 | 1120110022222222001120102 |
4 | 12131213030221320203 |
5 | 24234020412031034 |
6 | 540004522533015 |
7 | 44041351142231 |
oct | 6354714517043 |
9 | 1513288861512 |
10 | 444113002019 |
11 | 161390236765 |
12 | 720a466716b |
13 | 32b58858bbb |
14 | 176d0adb951 |
15 | b84452797e |
hex | 6767329e23 |
444113002019 has 2 divisors, whose sum is σ = 444113002020. Its totient is φ = 444113002018.
The previous prime is 444113001979. The next prime is 444113002031. The reversal of 444113002019 is 910200311444.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 444113002019 - 28 = 444113001763 is a prime.
It is a super-2 number, since 2×4441130020192 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 444113001982 and 444113002000.
It is not a weakly prime, because it can be changed into another prime (444113002049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222056501009 + 222056501010.
It is an arithmetic number, because the mean of its divisors is an integer number (222056501010).
Almost surely, 2444113002019 is an apocalyptic number.
444113002019 is a deficient number, since it is larger than the sum of its proper divisors (1).
444113002019 is an equidigital number, since it uses as much as digits as its factorization.
444113002019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
The spelling of 444113002019 in words is "four hundred forty-four billion, one hundred thirteen million, two thousand, nineteen".
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