Base | Representation |
---|---|
bin | 100000010100001001011… |
… | …1101001110011110001011 |
3 | 120201120210211021002211211 |
4 | 1000220102331032132023 |
5 | 1040231302420132021 |
6 | 13240151145233551 |
7 | 635605623006610 |
oct | 100502275163613 |
9 | 16646724232754 |
10 | 4441314224011 |
11 | 1462607104a55 |
12 | 5b890b1928b7 |
13 | 262a77864672 |
14 | 114d64454507 |
15 | 7a7de93a3e1 |
hex | 40a12f4e78b |
4441314224011 has 16 divisors (see below), whose sum is σ = 5505445471680. Its totient is φ = 3495520926720.
The previous prime is 4441314224003. The next prime is 4441314224023. The reversal of 4441314224011 is 1104224131444.
It is a cyclic number.
It is not a de Polignac number, because 4441314224011 - 23 = 4441314224003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4441314204011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 455141076 + ... + 455150833.
It is an arithmetic number, because the mean of its divisors is an integer number (344090341980).
Almost surely, 24441314224011 is an apocalyptic number.
4441314224011 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
4441314224011 is a deficient number, since it is larger than the sum of its proper divisors (1064131247669).
4441314224011 is a wasteful number, since it uses less digits than its factorization.
4441314224011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 910291974.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 4441314224011 its reverse (1104224131444), we get a palindrome (5545538355455).
The spelling of 4441314224011 in words is "four trillion, four hundred forty-one billion, three hundred fourteen million, two hundred twenty-four thousand, eleven".
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