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4442000113 is a prime number
BaseRepresentation
bin1000010001100001…
…11000101011110001
3102110120101222121201
410020300320223301
533044123000423
62012435251201
7215035243435
oct41060705361
912416358551
104442000113
11197a436481
12a3b749b01
1355a37a045
14301d2c9c5
151aee832ad
hex108c38af1

4442000113 has 2 divisors, whose sum is σ = 4442000114. Its totient is φ = 4442000112.

The previous prime is 4442000081. The next prime is 4442000117. The reversal of 4442000113 is 3110002444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3666544704 + 775455409 = 60552^2 + 27847^2 .

It is a cyclic number.

It is not a de Polignac number, because 4442000113 - 25 = 4442000081 is a prime.

It is not a weakly prime, because it can be changed into another prime (4442000117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2221000056 + 2221000057.

It is an arithmetic number, because the mean of its divisors is an integer number (2221000057).

Almost surely, 24442000113 is an apocalyptic number.

It is an amenable number.

4442000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4442000113 is an equidigital number, since it uses as much as digits as its factorization.

4442000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 4442000113 is about 66648.3316595397. The cubic root of 4442000113 is about 1643.8399156277.

Adding to 4442000113 its reverse (3110002444), we get a palindrome (7552002557).

The spelling of 4442000113 in words is "four billion, four hundred forty-two million, one hundred thirteen", and thus it is an aban number.