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44424014113 = 331134211523
BaseRepresentation
bin101001010111111000…
…001010100100100001
311020122222121201222001
4221113320022210201
51211440021422423
632224052444001
73131603614063
oct512770124441
9136588551861
1044424014113
111792721a356
128739619601
13425c7a2aab
142215d77733
1512500b5cad
hexa57e0a921

44424014113 has 4 divisors (see below), whose sum is σ = 44558225968. Its totient is φ = 44289802260.

The previous prime is 44424014087. The next prime is 44424014161. The reversal of 44424014113 is 31141042444.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44424014113 - 25 = 44424014081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44424014183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67105431 + ... + 67106092.

It is an arithmetic number, because the mean of its divisors is an integer number (11139556492).

Almost surely, 244424014113 is an apocalyptic number.

It is an amenable number.

44424014113 is a deficient number, since it is larger than the sum of its proper divisors (134211855).

44424014113 is a wasteful number, since it uses less digits than its factorization.

44424014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134211854.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 44424014113 its reverse (31141042444), we get a palindrome (75565056557).

The spelling of 44424014113 in words is "forty-four billion, four hundred twenty-four million, fourteen thousand, one hundred thirteen".

Divisors: 1 331 134211523 44424014113