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44425256230193 is a prime number
BaseRepresentation
bin10100001100111100011111…
…00111011101110100110001
312211022000100111020111210112
422012132033213131310301
521310330411043331233
6234252403031111105
712233422156263056
oct1206361747356461
9184260314214715
1044425256230193
1113178710a83653
124b95ab4512495
131ba338c34c127
14ad829ddc302d
15520909a08048
hex28678f9ddd31

44425256230193 has 2 divisors, whose sum is σ = 44425256230194. Its totient is φ = 44425256230192.

The previous prime is 44425256230151. The next prime is 44425256230217. The reversal of 44425256230193 is 39103265252444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36966059520784 + 7459196709409 = 6079972^2 + 2731153^2 .

It is a cyclic number.

It is not a de Polignac number, because 44425256230193 - 210 = 44425256229169 is a prime.

It is a super-2 number, since 2×444252562301932 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (44425256230793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22212628115096 + 22212628115097.

It is an arithmetic number, because the mean of its divisors is an integer number (22212628115097).

Almost surely, 244425256230193 is an apocalyptic number.

It is an amenable number.

44425256230193 is a deficient number, since it is larger than the sum of its proper divisors (1).

44425256230193 is an equidigital number, since it uses as much as digits as its factorization.

44425256230193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6220800, while the sum is 50.

The spelling of 44425256230193 in words is "forty-four trillion, four hundred twenty-five billion, two hundred fifty-six million, two hundred thirty thousand, one hundred ninety-three".