Base | Representation |
---|---|
bin | 1100111011100101111… |
… | …00010011000110101001 |
3 | 1120110211201201200020111 |
4 | 12131302330103012221 |
5 | 24234421332303001 |
6 | 540040242054321 |
7 | 44046263015011 |
oct | 6356274230651 |
9 | 1513751650214 |
10 | 444310041001 |
11 | 161481486aa2 |
12 | 7213a64a3a1 |
13 | 32b8a617508 |
14 | 1770cd4cc41 |
15 | b856999851 |
hex | 6772f131a9 |
444310041001 has 2 divisors, whose sum is σ = 444310041002. Its totient is φ = 444310041000.
The previous prime is 444310040959. The next prime is 444310041031. The reversal of 444310041001 is 100140013444.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 403001510976 + 41308530025 = 634824^2 + 203245^2 .
It is a cyclic number.
It is not a de Polignac number, because 444310041001 - 27 = 444310040873 is a prime.
It is a super-2 number, since 2×4443100410012 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (444310041031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222155020500 + 222155020501.
It is an arithmetic number, because the mean of its divisors is an integer number (222155020501).
Almost surely, 2444310041001 is an apocalyptic number.
It is an amenable number.
444310041001 is a deficient number, since it is larger than the sum of its proper divisors (1).
444310041001 is an equidigital number, since it uses as much as digits as its factorization.
444310041001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 444310041001 its reverse (100140013444), we get a palindrome (544450054445).
The spelling of 444310041001 in words is "four hundred forty-four billion, three hundred ten million, forty-one thousand, one".
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