Base | Representation |
---|---|
bin | 100000010101001000101… |
… | …0011111111010010000001 |
3 | 120201210021120012222212222 |
4 | 1000222101103333102001 |
5 | 1040300123113322241 |
6 | 13241141354100425 |
7 | 636012303561410 |
oct | 100522123772201 |
9 | 16653246188788 |
10 | 4443434120321 |
11 | 14634a47a2479 |
12 | 5b920111a715 |
13 | 263024aca691 |
14 | 1150c5bdd477 |
15 | 7a8b5ad2a4b |
hex | 40a914ff481 |
4443434120321 has 4 divisors (see below), whose sum is σ = 5078210423232. Its totient is φ = 3808657817412.
The previous prime is 4443434120309. The next prime is 4443434120327. The reversal of 4443434120321 is 1230214343444.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 4443434120321 - 210 = 4443434119297 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4443434120327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317388151445 + ... + 317388151458.
It is an arithmetic number, because the mean of its divisors is an integer number (1269552605808).
Almost surely, 24443434120321 is an apocalyptic number.
It is an amenable number.
4443434120321 is a deficient number, since it is larger than the sum of its proper divisors (634776302911).
4443434120321 is an equidigital number, since it uses as much as digits as its factorization.
4443434120321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 634776302910.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 4443434120321 its reverse (1230214343444), we get a palindrome (5673648463765).
The spelling of 4443434120321 in words is "four trillion, four hundred forty-three billion, four hundred thirty-four million, one hundred twenty thousand, three hundred twenty-one".
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