Base | Representation |
---|---|
bin | 1100111011110100010… |
… | …01101110001000110001 |
3 | 1120111011011100000221121 |
4 | 12131322021232020301 |
5 | 24240143314000423 |
6 | 540100242422241 |
7 | 44052262112332 |
oct | 6357211561061 |
9 | 1514134300847 |
10 | 444431000113 |
11 | 161533793401 |
12 | 72173061981 |
13 | 32ba96b8b59 |
14 | 17721038289 |
15 | b8623de45d |
hex | 677a26e231 |
444431000113 has 2 divisors, whose sum is σ = 444431000114. Its totient is φ = 444431000112.
The previous prime is 444431000099. The next prime is 444431000141. The reversal of 444431000113 is 311000134444.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 313580960289 + 130850039824 = 559983^2 + 361732^2 .
It is a cyclic number.
It is not a de Polignac number, because 444431000113 - 217 = 444430869041 is a prime.
It is a super-2 number, since 2×4444310001132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (444431000413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222215500056 + 222215500057.
It is an arithmetic number, because the mean of its divisors is an integer number (222215500057).
Almost surely, 2444431000113 is an apocalyptic number.
It is an amenable number.
444431000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
444431000113 is an equidigital number, since it uses as much as digits as its factorization.
444431000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 444431000113 its reverse (311000134444), we get a palindrome (755431134557).
The spelling of 444431000113 in words is "four hundred forty-four billion, four hundred thirty-one million, one hundred thirteen", and thus it is an aban number.
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