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444431000113 is a prime number
BaseRepresentation
bin1100111011110100010…
…01101110001000110001
31120111011011100000221121
412131322021232020301
524240143314000423
6540100242422241
744052262112332
oct6357211561061
91514134300847
10444431000113
11161533793401
1272173061981
1332ba96b8b59
1417721038289
15b8623de45d
hex677a26e231

444431000113 has 2 divisors, whose sum is σ = 444431000114. Its totient is φ = 444431000112.

The previous prime is 444431000099. The next prime is 444431000141. The reversal of 444431000113 is 311000134444.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 313580960289 + 130850039824 = 559983^2 + 361732^2 .

It is a cyclic number.

It is not a de Polignac number, because 444431000113 - 217 = 444430869041 is a prime.

It is a super-2 number, since 2×4444310001132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (444431000413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222215500056 + 222215500057.

It is an arithmetic number, because the mean of its divisors is an integer number (222215500057).

Almost surely, 2444431000113 is an apocalyptic number.

It is an amenable number.

444431000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

444431000113 is an equidigital number, since it uses as much as digits as its factorization.

444431000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 444431000113 its reverse (311000134444), we get a palindrome (755431134557).

The spelling of 444431000113 in words is "four hundred forty-four billion, four hundred thirty-one million, one hundred thirteen", and thus it is an aban number.