Base | Representation |
---|---|
bin | 100000011010000100100… |
… | …0100101001101010010001 |
3 | 120202210122020110010011111 |
4 | 1000310021010221222101 |
5 | 1040433330011100423 |
6 | 13250053223213321 |
7 | 636536045245255 |
oct | 100641104515221 |
9 | 16683566403144 |
10 | 4454033300113 |
11 | 1467a437550a1 |
12 | 5bb27a8a7241 |
13 | 2640239872b7 |
14 | 11580d774265 |
15 | 7acd639a60d |
hex | 40d09129a91 |
4454033300113 has 2 divisors, whose sum is σ = 4454033300114. Its totient is φ = 4454033300112.
The previous prime is 4454033300053. The next prime is 4454033300141. The reversal of 4454033300113 is 3110033304544.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4319613543424 + 134419756689 = 2078368^2 + 366633^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4454033300113 is a prime.
It is not a weakly prime, because it can be changed into another prime (4454033300173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2227016650056 + 2227016650057.
It is an arithmetic number, because the mean of its divisors is an integer number (2227016650057).
Almost surely, 24454033300113 is an apocalyptic number.
It is an amenable number.
4454033300113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4454033300113 is an equidigital number, since it uses as much as digits as its factorization.
4454033300113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 4454033300113 its reverse (3110033304544), we get a palindrome (7564066604657).
The spelling of 4454033300113 in words is "four trillion, four hundred fifty-four billion, thirty-three million, three hundred thousand, one hundred thirteen".
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