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44552500152113 is a prime number
BaseRepresentation
bin10100010000101001011111…
…11100100000011100110001
312211202011210100010111001102
422020110233330200130301
521314422010014331423
6234431045214014145
712245545325623262
oct1210245774403461
9184664710114042
1044552500152113
11132176779444a8
124bb66a61a7355
131bb238a234415
14b004d141c969
15523da590ac28
hex28852ff20731

44552500152113 has 2 divisors, whose sum is σ = 44552500152114. Its totient is φ = 44552500152112.

The previous prime is 44552500152001. The next prime is 44552500152203. The reversal of 44552500152113 is 31125100525544.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26124436996849 + 18428063155264 = 5111207^2 + 4292792^2 .

It is a cyclic number.

It is not a de Polignac number, because 44552500152113 - 28 = 44552500151857 is a prime.

It is not a weakly prime, because it can be changed into another prime (44552500052113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22276250076056 + 22276250076057.

It is an arithmetic number, because the mean of its divisors is an integer number (22276250076057).

Almost surely, 244552500152113 is an apocalyptic number.

It is an amenable number.

44552500152113 is a deficient number, since it is larger than the sum of its proper divisors (1).

44552500152113 is an equidigital number, since it uses as much as digits as its factorization.

44552500152113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120000, while the sum is 38.

Adding to 44552500152113 its reverse (31125100525544), we get a palindrome (75677600677657).

The spelling of 44552500152113 in words is "forty-four trillion, five hundred fifty-two billion, five hundred million, one hundred fifty-two thousand, one hundred thirteen".