Base | Representation |
---|---|
bin | 10100011101110100111101… |
… | …10010000010000011001011 |
3 | 12220100110121220201100112221 |
4 | 22032322132302002003023 |
5 | 21344331404244240321 |
6 | 235415055211514511 |
7 | 12323346030450043 |
oct | 1216723662020313 |
9 | 186313556640487 |
10 | 45005331243211 |
11 | 13381721222559 |
12 | 506a402458a37 |
13 | 1c15ca50071c1 |
14 | b183abd0a723 |
15 | 530a5a4c5e41 |
hex | 28ee9ec820cb |
45005331243211 has 4 divisors (see below), whose sum is σ = 45022043214432. Its totient is φ = 44988619271992.
The previous prime is 45005331243181. The next prime is 45005331243217. The reversal of 45005331243211 is 11234213350054.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 45005331243211 - 211 = 45005331241163 is a prime.
It is a super-2 number, since 2×450053312432112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (45005331243217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8355981571 + ... + 8355986956.
It is an arithmetic number, because the mean of its divisors is an integer number (11255510803608).
Almost surely, 245005331243211 is an apocalyptic number.
45005331243211 is a deficient number, since it is larger than the sum of its proper divisors (16711971221).
45005331243211 is a wasteful number, since it uses less digits than its factorization.
45005331243211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16711971220.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 45005331243211 its reverse (11234213350054), we get a palindrome (56239544593265).
The spelling of 45005331243211 in words is "forty-five trillion, five billion, three hundred thirty-one million, two hundred forty-three thousand, two hundred eleven".
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