Base | Representation |
---|---|
bin | 100000101111101110101… |
… | …0110001001110101110011 |
3 | 120221020200200011022002122 |
4 | 1001133131112021311303 |
5 | 1042214103322043443 |
6 | 13323304352104455 |
7 | 643103453423621 |
oct | 101373526116563 |
9 | 16836620138078 |
10 | 4500544331123 |
11 | 1485740a450a5 |
12 | 60829b23512b |
13 | 268526950619 |
14 | 117b82978511 |
15 | 7c1097b1968 |
hex | 417dd589d73 |
4500544331123 has 2 divisors, whose sum is σ = 4500544331124. Its totient is φ = 4500544331122.
The previous prime is 4500544331081. The next prime is 4500544331131. The reversal of 4500544331123 is 3211334450054.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4500544331123 is a prime.
It is a super-2 number, since 2×45005443311232 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4500544361123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2250272165561 + 2250272165562.
It is an arithmetic number, because the mean of its divisors is an integer number (2250272165562).
Almost surely, 24500544331123 is an apocalyptic number.
4500544331123 is a deficient number, since it is larger than the sum of its proper divisors (1).
4500544331123 is an equidigital number, since it uses as much as digits as its factorization.
4500544331123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 4500544331123 its reverse (3211334450054), we get a palindrome (7711878781177).
The spelling of 4500544331123 in words is "four trillion, five hundred billion, five hundred forty-four million, three hundred thirty-one thousand, one hundred twenty-three".
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