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4542383911193 is a prime number
BaseRepresentation
bin100001000011001101100…
…1011011111000100011001
3121002020200112201012001022
41002012123023133010121
51043410300240124233
613354424203332225
7646114336120622
oct102063313370431
917066615635038
104542383911193
1114a1461330947
12614417221075
1326c463b705ab
14119bd15a2a49
157d257a1e398
hex4219b2df119

4542383911193 has 2 divisors, whose sum is σ = 4542383911194. Its totient is φ = 4542383911192.

The previous prime is 4542383911139. The next prime is 4542383911201. The reversal of 4542383911193 is 3911193832454.

Together with previous prime (4542383911139) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4532164116544 + 10219794649 = 2128888^2 + 101093^2 .

It is a cyclic number.

It is not a de Polignac number, because 4542383911193 - 232 = 4538088943897 is a prime.

It is a super-2 number, since 2×45423839111932 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4542383911993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2271191955596 + 2271191955597.

It is an arithmetic number, because the mean of its divisors is an integer number (2271191955597).

Almost surely, 24542383911193 is an apocalyptic number.

It is an amenable number.

4542383911193 is a deficient number, since it is larger than the sum of its proper divisors (1).

4542383911193 is an equidigital number, since it uses as much as digits as its factorization.

4542383911193 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2799360, while the sum is 53.

The spelling of 4542383911193 in words is "four trillion, five hundred forty-two billion, three hundred eighty-three million, nine hundred eleven thousand, one hundred ninety-three".