Base | Representation |
---|---|
bin | 101010111101100100… |
… | …111000001100010011 |
3 | 11102001220011200211001 |
4 | 222331210320030103 |
5 | 1223433314443011 |
6 | 33105243002431 |
7 | 3222102343342 |
oct | 527544701423 |
9 | 142056150731 |
10 | 46130234131 |
11 | 18622350743 |
12 | 8b34b09417 |
13 | 4472119537 |
14 | 23387dbb59 |
15 | 12eec977c1 |
hex | abd938313 |
46130234131 has 2 divisors, whose sum is σ = 46130234132. Its totient is φ = 46130234130.
The previous prime is 46130234107. The next prime is 46130234173. The reversal of 46130234131 is 13143203164.
46130234131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 46130234131 - 229 = 45593363219 is a prime.
It is a super-2 number, since 2×461302341312 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 46130234131.
It is not a weakly prime, because it can be changed into another prime (46130234191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23065117065 + 23065117066.
It is an arithmetic number, because the mean of its divisors is an integer number (23065117066).
Almost surely, 246130234131 is an apocalyptic number.
46130234131 is a deficient number, since it is larger than the sum of its proper divisors (1).
46130234131 is an equidigital number, since it uses as much as digits as its factorization.
46130234131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 46130234131 its reverse (13143203164), we get a palindrome (59273437295).
The spelling of 46130234131 in words is "forty-six billion, one hundred thirty million, two hundred thirty-four thousand, one hundred thirty-one".
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