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461723213434753 is a prime number
BaseRepresentation
bin110100011111011110101000…
…0000111110000111110000001
32020112211022022121202010100201
41220332331100013300332001
5441004333120114403003
64314000414353445201
7166153254441404014
oct15076752007607601
92215738277663321
10461723213434753
11124134795980406
1243951075b70801
1316a83409ba01ca
14820374669937b
15385a73141eb1d
hex1a3ef501f0f81

461723213434753 has 2 divisors, whose sum is σ = 461723213434754. Its totient is φ = 461723213434752.

The previous prime is 461723213434739. The next prime is 461723213434781. The reversal of 461723213434753 is 357434312327164.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 401144497502464 + 60578715932289 = 20028592^2 + 7783233^2 .

It is a cyclic number.

It is not a de Polignac number, because 461723213434753 - 221 = 461723211337601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 461723213434694 and 461723213434703.

It is not a weakly prime, because it can be changed into another prime (461723213434733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 230861606717376 + 230861606717377.

It is an arithmetic number, because the mean of its divisors is an integer number (230861606717377).

Almost surely, 2461723213434753 is an apocalyptic number.

It is an amenable number.

461723213434753 is a deficient number, since it is larger than the sum of its proper divisors (1).

461723213434753 is an equidigital number, since it uses as much as digits as its factorization.

461723213434753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 30481920, while the sum is 55.

The spelling of 461723213434753 in words is "four hundred sixty-one trillion, seven hundred twenty-three billion, two hundred thirteen million, four hundred thirty-four thousand, seven hundred fifty-three".