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46478537121433 is a prime number
BaseRepresentation
bin10101001000101101000001…
…01100011101111010011001
320002120022020011111002001211
422210112200230131322121
522043001021000341213
6242503540054343121
712534651323011354
oct1244264054357231
9202508204432054
1046478537121433
111389a48956a64a
125267a2805aaa1
131cc1ba42a4981
14b69804c0729b
1555903040653d
hex2a45a0b1de99

46478537121433 has 2 divisors, whose sum is σ = 46478537121434. Its totient is φ = 46478537121432.

The previous prime is 46478537121427. The next prime is 46478537121551. The reversal of 46478537121433 is 33412173587464.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37709879060569 + 8768658060864 = 6140837^2 + 2961192^2 .

It is a cyclic number.

It is not a de Polignac number, because 46478537121433 - 213 = 46478537113241 is a prime.

It is not a weakly prime, because it can be changed into another prime (46478537127433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23239268560716 + 23239268560717.

It is an arithmetic number, because the mean of its divisors is an integer number (23239268560717).

Almost surely, 246478537121433 is an apocalyptic number.

It is an amenable number.

46478537121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

46478537121433 is an equidigital number, since it uses as much as digits as its factorization.

46478537121433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 40642560, while the sum is 58.

The spelling of 46478537121433 in words is "forty-six trillion, four hundred seventy-eight billion, five hundred thirty-seven million, one hundred twenty-one thousand, four hundred thirty-three".