Base | Representation |
---|---|
bin | 101011010110000001… |
… | …101000010000111011 |
3 | 11110010111000111212201 |
4 | 223112001220100323 |
5 | 1230303322034001 |
6 | 33214054451031 |
7 | 3235213036036 |
oct | 532601502073 |
9 | 143114014781 |
10 | 46540424251 |
11 | 18812946642 |
12 | 902a363a77 |
13 | 45090b8099 |
14 | 237709601d |
15 | 1325cc0501 |
hex | ad606843b |
46540424251 has 2 divisors, whose sum is σ = 46540424252. Its totient is φ = 46540424250.
The previous prime is 46540424239. The next prime is 46540424257. The reversal of 46540424251 is 15242404564.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 46540424251 - 25 = 46540424219 is a prime.
It is a super-2 number, since 2×465404242512 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 46540424251.
It is not a weakly prime, because it can be changed into another prime (46540424257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23270212125 + 23270212126.
It is an arithmetic number, because the mean of its divisors is an integer number (23270212126).
Almost surely, 246540424251 is an apocalyptic number.
46540424251 is a deficient number, since it is larger than the sum of its proper divisors (1).
46540424251 is an equidigital number, since it uses as much as digits as its factorization.
46540424251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 153600, while the sum is 37.
The spelling of 46540424251 in words is "forty-six billion, five hundred forty million, four hundred twenty-four thousand, two hundred fifty-one".
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