Base | Representation |
---|---|
bin | 100001111000101100101… |
… | …0001101000010000100001 |
3 | 121111020011020010001011011 |
4 | 1003301121101220100201 |
5 | 1102301013014424213 |
6 | 13523301350220521 |
7 | 660321543512632 |
oct | 103613121502041 |
9 | 17436136101134 |
10 | 4657242342433 |
11 | 153614198528a |
12 | 632731054741 |
13 | 27a239a8c985 |
14 | 1215a9b15889 |
15 | 8122b40703d |
hex | 43c59468421 |
4657242342433 has 4 divisors (see below), whose sum is σ = 4660382763568. Its totient is φ = 4654101921300.
The previous prime is 4657242342397. The next prime is 4657242342439. The reversal of 4657242342433 is 3342432427564.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4657242342433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4657242342439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1570208343 + ... + 1570211308.
It is an arithmetic number, because the mean of its divisors is an integer number (1165095690892).
Almost surely, 24657242342433 is an apocalyptic number.
It is an amenable number.
4657242342433 is a deficient number, since it is larger than the sum of its proper divisors (3140421135).
4657242342433 is a wasteful number, since it uses less digits than its factorization.
4657242342433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3140421134.
The product of its digits is 11612160, while the sum is 49.
Adding to 4657242342433 its reverse (3342432427564), we get a palindrome (7999674769997).
The spelling of 4657242342433 in words is "four trillion, six hundred fifty-seven billion, two hundred forty-two million, three hundred forty-two thousand, four hundred thirty-three".
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