Base | Representation |
---|---|
bin | 1101101101100110100… |
… | …01011011010010001011 |
3 | 1200001010220000110121211 |
4 | 12312303101123102023 |
5 | 30204413214001011 |
6 | 1000240355113551 |
7 | 46016522325142 |
oct | 6666321332213 |
9 | 1601126013554 |
10 | 471159125131 |
11 | 1718aa052322 |
12 | 773922a28b7 |
13 | 35578c68346 |
14 | 18b38b08759 |
15 | c3c8b6db21 |
hex | 6db345b48b |
471159125131 has 2 divisors, whose sum is σ = 471159125132. Its totient is φ = 471159125130.
The previous prime is 471159125113. The next prime is 471159125137. The reversal of 471159125131 is 131521951174.
Together with previous prime (471159125113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 471159125131 - 215 = 471159092363 is a prime.
It is a super-2 number, since 2×4711591251312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (471159125137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 235579562565 + 235579562566.
It is an arithmetic number, because the mean of its divisors is an integer number (235579562566).
Almost surely, 2471159125131 is an apocalyptic number.
471159125131 is a deficient number, since it is larger than the sum of its proper divisors (1).
471159125131 is an equidigital number, since it uses as much as digits as its factorization.
471159125131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 37800, while the sum is 40.
The spelling of 471159125131 in words is "four hundred seventy-one billion, one hundred fifty-nine million, one hundred twenty-five thousand, one hundred thirty-one".
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