47120134153 has 4 divisors (see below), whose sum is σ = 47273620240. Its totient is φ = 46966648068.

The previous prime is 47120134133. The next prime is 47120134157. The reversal of 47120134153 is 35143102174.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35143102174 = 2 ⋅17571551087.

It is a cyclic number.

It is not a de Polignac number, because 47120134153 - 2¹⁷ = 47120003081 is a prime.

It is a super-5 number, since 5×47120134153⁵ (a number of 55 digits) contains 55555 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (47120134157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76742583 + ... + 76743196.

It is an arithmetic number, because the mean of its divisors is an integer number (11818405060).

Almost surely, 2^47120134153 is an apocalyptic number.

It is an amenable number.

47120134153 is a deficient number, since it is larger than the sum of its proper divisors (153486087).

47120134153 is a wasteful number, since it uses less digits than its factorization.

47120134153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 153486086.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 47120134153 in words is "forty-seven billion, one hundred twenty million, one hundred thirty-four thousand, one hundred fifty-three".