Base | Representation |
---|---|
bin | 10101011110000110000101… |
… | …11101101110011110110011 |
3 | 20012011120102120200010012221 |
4 | 22233003002331232132303 |
5 | 22142021323134304312 |
6 | 244225334531101511 |
7 | 12642031550656225 |
oct | 1257030275563663 |
9 | 205146376603187 |
10 | 47213551478707 |
11 | 14053177a56099 |
12 | 5366376a41897 |
13 | 20462ac9214c3 |
14 | b932104b4415 |
15 | 56d1ed428207 |
hex | 2af0c2f6e7b3 |
47213551478707 has 2 divisors, whose sum is σ = 47213551478708. Its totient is φ = 47213551478706.
The previous prime is 47213551478537. The next prime is 47213551478729. The reversal of 47213551478707 is 70787415531274.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 47213551478707 - 211 = 47213551476659 is a prime.
It is a super-3 number, since 3×472135514787073 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (47213551488707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23606775739353 + 23606775739354.
It is an arithmetic number, because the mean of its divisors is an integer number (23606775739354).
Almost surely, 247213551478707 is an apocalyptic number.
47213551478707 is a deficient number, since it is larger than the sum of its proper divisors (1).
47213551478707 is an equidigital number, since it uses as much as digits as its factorization.
47213551478707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46099200, while the sum is 61.
The spelling of 47213551478707 in words is "forty-seven trillion, two hundred thirteen billion, five hundred fifty-one million, four hundred seventy-eight thousand, seven hundred seven".
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