Base | Representation |
---|---|
bin | 10101011111110110101110… |
… | …11011001111010110101001 |
3 | 20012101100112000221211120201 |
4 | 22233323113123033112221 |
5 | 22144014200210130433 |
6 | 244313215325352201 |
7 | 12646302251331406 |
oct | 1257732733172651 |
9 | 205340460854521 |
10 | 47274024301993 |
11 | 1407688a3182a5 |
12 | 5376033108661 |
13 | 204bbc9309888 |
14 | b96109a872ad |
15 | 56ea8c426a7d |
hex | 2afed76cf5a9 |
47274024301993 has 2 divisors, whose sum is σ = 47274024301994. Its totient is φ = 47274024301992.
The previous prime is 47274024301961. The next prime is 47274024302083. The reversal of 47274024301993 is 39910342047274.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 47054839280409 + 219185021584 = 6859653^2 + 468172^2 .
It is a cyclic number.
It is not a de Polignac number, because 47274024301993 - 25 = 47274024301961 is a prime.
It is not a weakly prime, because it can be changed into another prime (47274064301993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23637012150996 + 23637012150997.
It is an arithmetic number, because the mean of its divisors is an integer number (23637012150997).
Almost surely, 247274024301993 is an apocalyptic number.
It is an amenable number.
47274024301993 is a deficient number, since it is larger than the sum of its proper divisors (1).
47274024301993 is an equidigital number, since it uses as much as digits as its factorization.
47274024301993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9144576, while the sum is 55.
The spelling of 47274024301993 in words is "forty-seven trillion, two hundred seventy-four billion, twenty-four million, three hundred one thousand, nine hundred ninety-three".
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