Base | Representation |
---|---|
bin | 101100001100001111… |
… | …100111101001011011 |
3 | 11112110212122212110121 |
4 | 230030033213221123 |
5 | 1234134203431103 |
6 | 33444231254111 |
7 | 3266566603303 |
oct | 541417475133 |
9 | 145425585417 |
10 | 47450061403 |
11 | 1913a360488 |
12 | 9242b1a337 |
13 | 46226a7114 |
14 | 2421c00603 |
15 | 137aaa26bd |
hex | b0c3e7a5b |
47450061403 has 2 divisors, whose sum is σ = 47450061404. Its totient is φ = 47450061402.
The previous prime is 47450061391. The next prime is 47450061419. The reversal of 47450061403 is 30416005474.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47450061403 is a prime.
It is not a weakly prime, because it can be changed into another prime (47450061803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23725030701 + 23725030702.
It is an arithmetic number, because the mean of its divisors is an integer number (23725030702).
Almost surely, 247450061403 is an apocalyptic number.
47450061403 is a deficient number, since it is larger than the sum of its proper divisors (1).
47450061403 is an equidigital number, since it uses as much as digits as its factorization.
47450061403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 47450061403 its reverse (30416005474), we get a palindrome (77866066877).
The spelling of 47450061403 in words is "forty-seven billion, four hundred fifty million, sixty-one thousand, four hundred three".
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