Base | Representation |
---|---|
bin | 1101110101100000100… |
… | …10011101100000001011 |
3 | 1200110002201120002011011 |
4 | 12322300102131200023 |
5 | 30242111413011021 |
6 | 1002221514144351 |
7 | 46226645412016 |
oct | 6726022354013 |
9 | 1613081502134 |
10 | 475404032011 |
11 | 173688200727 |
12 | 78177a220b7 |
13 | 35aa453816c |
14 | 1901c7b037d |
15 | c57666dde1 |
hex | 6eb049d80b |
475404032011 has 2 divisors, whose sum is σ = 475404032012. Its totient is φ = 475404032010.
The previous prime is 475404031919. The next prime is 475404032057. The reversal of 475404032011 is 110230404574.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-475404032011 is a prime.
It is not a weakly prime, because it can be changed into another prime (475404032611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 237702016005 + 237702016006.
It is an arithmetic number, because the mean of its divisors is an integer number (237702016006).
Almost surely, 2475404032011 is an apocalyptic number.
475404032011 is a deficient number, since it is larger than the sum of its proper divisors (1).
475404032011 is an equidigital number, since it uses as much as digits as its factorization.
475404032011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 475404032011 its reverse (110230404574), we get a palindrome (585634436585).
The spelling of 475404032011 in words is "four hundred seventy-five billion, four hundred four million, thirty-two thousand, eleven".
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