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47780203435331 is a prime number
BaseRepresentation
bin10101101110100101100100…
…00011011001010101000011
320021011202001112022001020112
422313102302003121111003
522230312324034412311
6245341531125101535
713031001661065053
oct1267226203312503
9207152045261215
1047780203435331
111425151a237064
1254381595578ab
132087866682963
14bb28077c9563
1557cd1577928b
hex2b74b20d9543

47780203435331 has 2 divisors, whose sum is σ = 47780203435332. Its totient is φ = 47780203435330.

The previous prime is 47780203435301. The next prime is 47780203435417. The reversal of 47780203435331 is 13353430208774.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 47780203435331 - 230 = 47779129693507 is a prime.

It is a super-3 number, since 3×477802034353313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 47780203435331.

It is not a weakly prime, because it can be changed into another prime (47780203435301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23890101717665 + 23890101717666.

It is an arithmetic number, because the mean of its divisors is an integer number (23890101717666).

Almost surely, 247780203435331 is an apocalyptic number.

47780203435331 is a deficient number, since it is larger than the sum of its proper divisors (1).

47780203435331 is an equidigital number, since it uses as much as digits as its factorization.

47780203435331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 50.

The spelling of 47780203435331 in words is "forty-seven trillion, seven hundred eighty billion, two hundred three million, four hundred thirty-five thousand, three hundred thirty-one".