Base | Representation |
---|---|
bin | 101100100010101010… |
… | …001101011000000001 |
3 | 11120110002022011012012 |
4 | 230202222031120001 |
5 | 1240421442133213 |
6 | 33545423542305 |
7 | 3312114254414 |
oct | 544252153001 |
9 | 146402264165 |
10 | 47826130433 |
11 | 19312670734 |
12 | 9328a5a995 |
13 | 4682589c83 |
14 | 2459b35b7b |
15 | 139dada4a8 |
hex | b22a8d601 |
47826130433 has 4 divisors (see below), whose sum is σ = 48102582228. Its totient is φ = 47549678640.
The previous prime is 47826130423. The next prime is 47826130439. The reversal of 47826130433 is 33403162874.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 24789872704 + 23036257729 = 157448^2 + 151777^2 .
It is a cyclic number.
It is not a de Polignac number, because 47826130433 - 230 = 46752388609 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (47826130439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138225638 + ... + 138225983.
It is an arithmetic number, because the mean of its divisors is an integer number (12025645557).
Almost surely, 247826130433 is an apocalyptic number.
It is an amenable number.
47826130433 is a deficient number, since it is larger than the sum of its proper divisors (276451795).
47826130433 is a wasteful number, since it uses less digits than its factorization.
47826130433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 276451794.
The product of its (nonzero) digits is 290304, while the sum is 41.
The spelling of 47826130433 in words is "forty-seven billion, eight hundred twenty-six million, one hundred thirty thousand, four hundred thirty-three".
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